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2.1.7 Calculating Truss Forces May 2026

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: AB = +5 kN → Tension (member is being stretched). AC = –7.07 kN → Compression (member is being shortened → risk of buckling).

Joint A (left bottom): Forces: AB (to right), AC (up-right, 45°), reaction 5 kN up. ΣFy = 0: AC·sin45° + 5 = 0 → AC = –7.07 kN (compression). ΣFx = 0: AB + AC·cos45° = 0 → AB = 5 kN (tension).

ΣM(left pin) = 0 → Right reaction × 6 m – 10 kN × 3 m = 0 → Right = 5 kN ↑ ΣFy = 0 → Left reaction = 5 kN ↑ ΣFx = 0 → Left horizontal = 0.

2.1.7 Calculating Truss Forces May 2026

: AB = +5 kN → Tension (member is being stretched). AC = –7.07 kN → Compression (member is being shortened → risk of buckling).

Joint A (left bottom): Forces: AB (to right), AC (up-right, 45°), reaction 5 kN up. ΣFy = 0: AC·sin45° + 5 = 0 → AC = –7.07 kN (compression). ΣFx = 0: AB + AC·cos45° = 0 → AB = 5 kN (tension). 2.1.7 calculating truss forces

ΣM(left pin) = 0 → Right reaction × 6 m – 10 kN × 3 m = 0 → Right = 5 kN ↑ ΣFy = 0 → Left reaction = 5 kN ↑ ΣFx = 0 → Left horizontal = 0. : AB = +5 kN → Tension (member is being stretched)